2y^2=260

Solution for 2y^2=260 equation:

2y^2=260

We move all terms to the left:

2y^2-(260)=0

a = 2; b = 0; c = -260;
Δ = b2-4ac
Δ = 02-4·2·(-260)
Δ = 2080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2080}=\sqrt{16*130}=\sqrt{16}*\sqrt{130}=4\sqrt{130}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{130}}{2*2}=\frac{0-4\sqrt{130}}{4}
=-\frac{4\sqrt{130}}{4}
=-\sqrt{130}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{130}}{2*2}=\frac{0+4\sqrt{130}}{4}
=\frac{4\sqrt{130}}{4}
=\sqrt{130}
$